try and lock question

i have a question .. is开发者_C百科 it ok if i have something like this :

try 
{ 
    lock(programLock) 
    {
         //some stuff 1
    }
}
catch(Exception ex) { //stuff 2 }

i am curious if "some stuff 1" causes an exception , does programLock still remains locked ?

---

No, the lock will be released, lock is roughly equivalent to this:

try
{
    Monitor.Enter(programLock);
    // some stuff 1
}
finally
{
    Monitor.Exit(programLock);
}

(Meaning if an exception is thrown, Monitor.Exit will get called automatically as you exit the scope of the lock statement)

---

Lock() is nothing but

try
{
   Monitor.Enter(...);
}
finally
{
   Monitor.Exit(....);
}

So it already takes care of it.

---

From msdn documentation

"... lock or SyncLock insures that the underlying monitor is released, even if the protected code throws an exception."

note: You can create your own exception safe blocks for arbitrary actions with using blocks, .net's version of the RAII idiom.

---

No. leaving the lock braces will always unlock.

---

No, it will not remain locked.

The "closing brace" of the lock is basically the finally clause of the Monitor.Exit.

See this associated StackOverflow Question.

Does a locked object stay locked if an exception occurs inside it?