I have a script that needs to take in the name of a file and a set of key=value pairs. The set of key=value pairs is not defined. They are dependent on the file that was passed in.

eg:

Script.py file1 bob=1 sue=2 ben=3  # file 1 needs bob, sue, and ben

Script.py file2 mel=1 gorge=3 steve=3 # file 2 needs mel, gorge, and steve

Is this possible with argpa开发者_运维技巧rse / optparse or do I have to build my own parser?

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That should be fairly easy to parse yourself. Use of the helper libraries would be complicated by not knowing the keys in advance. The filename is in sys.argv[1]. You can build the dictionary with a list of strings split with the '=' character as a delimiter.

import sys
filename = sys.argv[1]
args = dict([arg.split('=', maxsplit=1) for arg in sys.argv[2:]])
print filename
print args

Output:

$ Script.py file1 bob=1 sue=2 ben=3
file1
{'bob': '1', 'ben': '3', 'sue': '2'}

That's the gist of it, but you may need more robust parsing of the key-value pairs than just splitting the string. Also, make sure you have at least two arguments in sys.argv before trying to extract the filename.

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Hope this helps, instead of passing a dict you can pass an "escaped" json string as a command line argument

import optparse
import json

parser = optparse.OptionParser()
parser.add_option("-t", "--test", dest="test", action="store", type="string")
options, _ = parser.parse_args()
my_dict = json.loads(options.test)
print my_dict['key1']

then use it as so:

python test.py -t "{\"key1\":\"value1\",\"key2\":\"value2\"}"

this will output "value1"

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Here is an example:

Example: 1:

# runline argument is : ./filename fname=sameer sname=ali age=29
import sys 

l = sys.argv[1:]

print(l)

l = ['fname=sameer', 'sname=ali', 'age=29']

for i in l:

    runarg = i.split('=')

    d[runarg[0]] = runarg[1]

print(d)

{'fname': 'sameer', 'sname': 'ali', 'age': '29'}

Example: 2

print(sys.argv[1:]

ouput: ['fname=sameer', 'sname=ali', 'age=29']

newlist = [x.split('=') for x in l] print(newlist)

output: [['fname', 'sameer'], ['sname', 'ali'], ['age', '29']]

newdict = dict(newlist)

print(newdict)

output: {'fname': 'sameer', 'sname': 'ali', 'age': '29'}