Pointer to an array of function pointers

int (*rdPtrList[4])(unsigned int addr, unsigned int data);

The above declares an array of size 4 of pointers for functions that returns an int and takes开发者_StackOverflow two unsigned int. I would like to make a pointer to this array. Is this possible in C?

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Leaving out the parameters to keep the following easier to read:

        p         -- p
       *p         -- is a pointer
      (*p)[4]     -- to a 4-element array
     *(*p)[4]     -- of pointers
    (*(*p)[4])()  -- to functions 
int (*(*p)[4])(); -- returning int. 

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Ah, tricky tricky!!!

I think this works

int (*(*rdPtrList)[4])(unsigned int addr, unsigned int data);

because the compiler tells me _countof(*rdPtrList) is 4.

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(I wish you could just say int function(unsigned int addr, unsigned int data)[4]* like you can in D, it's so much more readable: it would be a "function array pointer".)

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Try this:

typedef int(*rdPtrList_t[4])(unsigned int addr, unsigned int data);
rdPtrList_t *ptrToArray;