开发者

PROJECT_ROOT = os.path.dirname(__file__) error

开发者 https://www.devze.com 2023-02-22 19:41 出处:网络
When i try: PROJECT_ROOT = os.path.dirname(__file__) i get error like this: Traceback (mos开发者_Go百科t recent call last):

When i try:

PROJECT_ROOT = os.path.dirname(__file__)

i get error like this:

Traceback (mos开发者_Go百科t recent call last):

File "< stdin>", line 1, in <module>

NameError: name '__file__' is not defined

Does someone know how to fix this?


Run that line of code via an actual module instead of in the Python REPL.


If you are trying to use __file__ from your interpreter, no __file__ is defined. This is the intended behavior. __file__ is an attribute of modules. Here is a discussion about the subject.

You can test by doing this:

~$ echo "print __file__" > test.py
~$ python test.py
test.py

__file__ works in from within modules.

Now from the interpreter:

~$ python
Python 2.7.0+ (r27:82500, Sep 15 2010, 18:04:55) 
[GCC 4.4.5] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> print __file__
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
NameError: name '__file__' is not defined

__file__ is not defined

>>> import test
test.pyc
>>> print __file__
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
NameError: name '__file__' is not defined

__file__ is not defined

>>> print test.__file__
test.pyc
>>> 

__file__ is defined for the test module


Please try this in your settings.py :

    PROJECT_ROOT = os.path.abspath(os.path.dirname(__file__))
0

精彩评论

暂无评论...
验证码 换一张
取 消