I couldn't find much when I searched for s开发者_JAVA百科tandard deviations and population variances on fortran 95. So I'm wondering if someone could help me? Thanks for your time.
Here is what I did, it compiled fine but it turned out giving wrong values:
SUBROUTINE ComputeStats(num, sum, avg, variance, sdv)
REAL, INTENT(IN):: num(10)
REAL, INTENT(OUT):: sum
REAL, INTENT(OUT):: avg, variance, sdv
DO i=1, 10
sum=sum+num(i)
END DO
avg=sum/10
DO i=1, 10
variance=(((num(i)-avg)**2.0)/10)
variance=variance+i
sdv=variance**0.5
END DO
END SUBROUTINE
You don't calculate the variance correctly.
variance = 0
DO i=1, 10
variance = variance + (((num(i)-avg)**2.0)/10)
END DO
This gives you the right variance for e.g. 1,1,1,1,1,1,1,1,1,1 which is 0, not 10.
A simple subroutine for finding the standard deviation of an array
subroutine find_std(n,arr,std_dev)
integer,intent(in)::n
real,intent(in),dimension(n)::arr
real,intent(out)::std_dev
real::variance, avg
integer::i
avg=sum(arr)/n
variance=0.
do i=1,n
variance=variance+(arr(i)-avg))**2
end do
variance=variance/n
std_dev=sqrt(variance)
end subroutine
The size of the array is passed here as the first argument (n). We can circumvent this by using an assumed-shape array and putting the subroutine under an explicit interface like module or an interface block.
subroutine find_std(arr,std_dev)
real,intent(in),dimension(:)::arr
real,intent(out)::std_dev
real::variance, avg
integer::n,i
n=size(arr)
avg=sum(arr)/n
variance=0.
do i=1,n
variance=variance+(arr(i)-avg)**2
end do
variance=variance/n
std_dev=sqrt(variance)
end subroutine
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