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How do I fix a Java Priority-Queue to correctly sort by a specific property?

开发者 https://www.devze.com 2023-02-22 12:44 出处:网络
I have a Java PriorityQueue for sorting objects from a specific class I made called Node. I want it to sort the Nodes by their getData() method. I tried the following code (using a comparator), but it

I have a Java PriorityQueue for sorting objects from a specific class I made called Node. I want it to sort the Nodes by their getData() method. I tried the following code (using a comparator), but it did not work. When I called the priority queue's "poll" method, it did not return the lowest results first, but in a seemingly random order. How do I fix it? Thanks!

PriorityQueue<Node> pq = new PriorityQueue<Node>(hm.size(),
        new Comparator<Node>( ) {
            // override the compare method
     开发者_开发百科       public int compare(Node i, Node j) {
                if (i.getData()<j.getData()){
                                        return i.getData(); //It should sort by the Node's getData method.
                                    }
                                    return j.getData();


A comparator needs to return -1 (a negative number), 0 or +1 (a positive number) depending on whether the first operand is less-than, equal-to or greater-than the second operand. You are returning the data itself which won't do what you want.


Rewrite the compare method:

public int compare(Node i, Node j) {
  return i.getData() - j.getData()
}

This will follow requirements of compare method to return value less, equal or more than zero depending on comparison result.

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