Extracting string from main() arguments

I am trying to create a pointer to one of the main() arguments in my program. I set up the initial pointer, then I set it equal to the 2nd element in the array, but I get an error when I try to compile, segmentation fault. Does this occur because a pointer is pointing to a bad address?

Here is the code:

char *filename;
*filename = argv[1];
printf("The filename is: %s", *filename);

I get errors about the pointer trying to cast the argument as an int. Is this because the pointer is actually an integer address value and I am trying to set it equal to a string?

Edit: When I change to "filename = argv[1]", then I get the following error from my c开发者_高级运维ompiler: assignment discards qualifiers from pointer target type.

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A segmentation fault couldn't possibly occur when you compile. Unless, well, the compiler violates memory safety, which is unlikely. I'll take it that it happens when you run the program :D.

The problem is here:

*filename = argv[1];

It should be:

filename = argv[1];

Why? You declared a pointer to char, unitialized, poiting nowhere in particular. Then, you dereferenced that pointer and assigned data to that memory position. Which is, well, who knows where!

Edit: you also dereference filename in the printf() call. Remove that * :).

Also, didnt' the compiler shoot a warning when you assigned *filename? Making integer from pointer without a cast, would be my guess? Pay attention to the warnings, they provide useful information!

Cheers.

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You're not making filename point to the same place as argv[1]. To do that you need

filename = argv[1];

With your version (*filename = argv[1];) you're trying to make whatever filename points to have the value that is in argv[1]. There's lots of stuff wrong with this: a) filename is not initialized and can point anywhere, even invalid locations; b) argv[1] is of type char* and you're trying to put it into a location of type char!

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In the statement *filename = argv[1];, the expression *filename attempts to dereference (find the value pointed to) the filename pointer, which is not yet pointing anywhere meaningful.

Change the assignment to filename = argv[1].

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You're dereferencing the char* when you try to assign it, so you're trying to stuff a pointer into a char. And since filename is uninitialized, you're trying to hit some random address (or perhaps address 0x00000000. And your print statement, if you got that far, wouldn't work either: you're again dereferencing the char* (to get a char) and then telling printf to interpret that as a pointer to a nul-terminated string.

Try this:

char *filename ;
filename = argv[1] ;
printf( "The filename is: %s" , filename ) ;