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How does one compare a char variable to another char variable?

开发者 https://www.devze.com 2023-02-21 21:10 出处:网络
I\'m working开发者_开发问答 on a homework assignment in C where we need to make a tic-tac-toe game that can be played between two players.I have all of my code working at this point, except for the fu

I'm working开发者_开发问答 on a homework assignment in C where we need to make a tic-tac-toe game that can be played between two players. I have all of my code working at this point, except for the function that checks to find a winner. Here's an example of the outcome of a game I tested with:

  0 1 2
0  |x| 
  -----
1  |o| 
  -----
2  |x| 
Congratulations to player 1!  You won!

To which I say, no. No, player 1 definitely didn't win. My checks are (forgive me) a series of nested if statements like so:

...
else if (gameboard[0][1] != ' ')
    if (gameboard[1][1] == gameboard[0][1])
        if(gameboard[2][1] == gameboard[1][1])
            return 1;
...

gameboard[0][1] is an 'x' value, yet the comparison says that gameboard[1][1] is equal to it. Why is this happening and how do I fix it?


Your gameboard might be set up differently from what you are thinking.

#include <stdio.h>

int main()
{
    char gameboard[3][3] =
    { {' ', 'x', ' '},
      {' ', 'o', ' '},
      {' ', 'x', ' '}
    };

    if (gameboard[0][0] == ' ')
    {
        printf("0,0 is empty\n");
    }

    if (gameboard[0][1] != ' ')
    {
        printf("0,1 has %c\n", gameboard[0][1]);
    }

    if (gameboard[1][1] == gameboard[0][1])
    {
        printf("1,1 equals 0,1\n");
    }
    else
    {
        printf("1,1 is different from 0,1\n");
    }    
}

Outputs:

0,0 is empty
0,1 has x
1,1 is different from 0,1
0

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