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Type of conditional expression cannot be determined as

开发者 https://www.devze.com 2023-02-21 20:44 出处:网络
When I compile my C# project in MonoDevelop, I get the following error: Type of conditional expression cannot be determined as \'byte\' and \'int\' convert implicitly to each other

When I compile my C# project in MonoDevelop, I get the following error:

Type of conditional expression cannot be determined as 'byte' and 'int' convert implicitly to each other

Code Snippet:

byte oldType = type;
type = bindings[type];
//Ignores upda开发者_运维技巧ting blocks that are the same and send block only to the player
if (b == (byte)((painting || action == 1) ? type : 0))
{
    if (painting || oldType != type) { SendBlockchange(x, y, z, b); } return;
}

This is the line that is highlighted in the error:

if (b == (byte)((painting || action == 1) ? type : 0))

Help is greatly appreciated!


The conditional operator is an expression and thus needs a return type, and both paths have to have the same return type.

(painting || action == 1) ? type : (byte)0


There is no implicit conversion between byte and int, so you need to specify one in the results of the ternary operator:

? type : (byte)0

Both return types on this operator need to either be the same or have an implicit conversion defined in order to work.

From MSDN ?: Operator:

Either the type of first_expression and second_expression must be the same, or an implicit conversion must exist from one type to the other.

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