What is the best way to pick out the last quarter of the elements in a vect开发者_开发问答or containg N elements?
size_t n = src.size();
std::vector<int> dest(src.begin() + (3*n)/4, src.end());
dest
contains the last quarter elements from the source vector src
.
You can also use std::copy
from <algorithm>
header file as,
std::vector<int> dest_copy;
std::copy(src.begin() + (3*n)/4, src.end(), std::back_inserter(dest_copy));
See the online demo at ideone : http://ideone.com/qrVod
I think, you may want to work more on the expression (3*n)/4
. Like when n
is say 5, you want to pick 1
element only, but when n
is 7
, you may want to pick 2
instead of 1
. So this decision is upto you. My solution just tells you how would you copy the elements, once you decide exactly how many!
Something like this, I guess:
size_t lastQuarter = myVector.size() * 3 / 4;
for (size_t i = lastQuarter; i < myVector.size(); i++)
{
doSomething(myVector.at(i));
}
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