I only know what I know through my experience through Computer Architecture course. Little-endian stores the LSB on the right and MSB on the left and on Big-endian it's vice versa.
That would mean a byte re开发者_运维知识库presentation of 18 is 0001 0010 and on Big-endian it would be 0100 1000.
No, it is not like that, say you have 3,168,415,017
as 32 bit unsigned number here is the Little Endian binary representation of it:
10111100 11011010 00101101 00101001
While the Big Endian representation would flip the BYTES but not the BITS inside the bytes.
00101001 00101101 11011010 10111100
Note that the bytes are flipped but the order of bits inside of each remains the same.
精彩评论