How can I combine my two regular expressions and save the results as variable?

I get all the images with this

preg_match_all('!http://.+\.(?:jpe?g|png|gif)!Ui' , $content , $matches);

and this is how i block all the image if it has a "bad word"

'/(list|of|bad|words)/i'

How can I combine them and save the result inst开发者_运维技巧ead in variable instead of print_r? My purpose is to delete from content all those images and produce the "clean" content.

Thank you!

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Probably the fastest way is to run the first regex and then filter out the bad ones later. You could probably do this with a callback rather easily. I wouldn't try to combine the regex though.

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Might require some tweaking depending on how $content is formatted:

<?php
    $content = 'http://www.example.com/images/image001.jpg 
                http://www.example.com/images/image002.jpeg 
                http://www.example.com/images/list001.jpg 
                http://www.example.com/images/image003.png 
                http://www.example.com/images/bad002.png 
                http://www.example.com/images/image004.gif 
                http://www.example.com/images/words003.jpg';

    preg_match_all('!http://.+\.(?:jpe?g|png|gif)!Ui', $content, $matches);

    preg_match_all('/\S+(list|of|bad|words)\S+/i', $content, $bads);

    $filtered = array_values(array_diff($matches[0], $bads[0]));

    print_r($filtered);
?>

Output:

Array
(
    [0] => http://www.example.com/images/image001.jpg
    [1] => http://www.example.com/images/image002.jpeg
    [2] => http://www.example.com/images/image003.png
    [3] => http://www.example.com/images/image004.gif
)