I'm retrieving contact names with this code:
for( int i = 0 ; i < n ; i++ )
{
Contact *c = [[Contact alloc] init];
ABRecordRef ref = CFArrayGetValueAtIndex(all, i);
NSString *firstName = (NSString *)ABRecordCopyValue(ref, kABPersonFirstNameProperty);
NSString *lastName = (NSString *)ABRecordCopyValue(ref, kABPersonLastNameProperty);
c.firstName = firstName; //[NSString stringWithFormat:@"%@ %@", firstName, lastName];
c.lastName = lastName;
[contacts addObject:c];
[c release];
}
Does anyone know a way of ordering this list alphabetically? I've read about sortedArrayUsingSelector:@selector(co开发者_开发问答mpare:)
but I have no idea how that is supposed to work.
NSSortDescriptor *mySorter = [[NSSortDescriptor alloc] initWithKey:@"lastName" ascending:YES];
[contacts sortUsingDescriptors:[NSArray arrayWithObject:mySorter]];
[mySorter release];
This method will let you respect the user's preferences for sorting by first or last name.
contacts = (bridgedPeople as [ABRecord]).sort {
(person1, person2) -> Bool in
return .CompareLessThan == ABPersonComparePeopleByName(person1, person2, ABPersonGetSortOrdering())
}
Pro-tip: Boldface the part of the name that you're sorting on; otherwise it gets confusing when you mix contacts who have [no first name, no last name, first and last name]
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