Opening program by double-clicking associated file, can't get filename!

I have a program that has a file type associated with it (*.cqd). When the user double clicks a .cqd file, it opens up my program just fine, but I can't for the life of me get the name/path of the file used to open the program.

I've tried the following code:

public static void Main(string[] args)
{
    foreach (string s in args)
    {
        MessageBox.Show("MAIN: " + s);
    }
}

Which only gives me the path of the program itself.

I've also tried:

foreach (string arg in Environment.GetCommandLineArgs())
{
     MessageBox.Show(arg);
}

Which has the same effect. I'm having a hard time finding information on the topic because my searches give me "How do I open a file with it's associated program?" rather than the problem I'm having. Any help I can get would be appreciated.

NINJA EDIT: This is not a WPF project. Sorry I wasn't specific on that. I also fixed a quick typo.

开发者_如何学编程

FOUND THE PROBLEM! When I publish the application, it publishes to a .application file. I went into the project's /bin/release/ folder and found the .exe file. When I drag a file onto the .exe, it properly passes the path into the arguments. Guess I need to read up more on why this is, and if I can get the .application file to work with arguments, seeing as how it has the auto-update of ClickOnce in it.

Thank you all for your help! If there's anything I need to do to close this thread, please let me know.

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AppDomain.CurrentDomain.SetupInformation.ActivationArguments.ActivationData[0]

Works as well for ClickOnce activations

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Perhaps you meant:

public static void Main(string[] args)
 {
     foreach (string s in args)
     {
         MessageBox.Show("MAIN: " + s);
     }
 } 

---

This blog post details your exact problem, and the solution.

But, in short, it's not stored in args, it's stored in:

AppDomain.CurrentDomain.SetupInformation.ActivationArguments.ActivationData[0]

(This is all assuming you're using WPF)

---

In App.xaml.cs

 protected override void OnStartup(StartupEventArgs e)
    {
        if (e.Args != null && e.Args.Length > 0)
        {
            //MessageBox.Show("dgda");
            //DirectOpenPath = e.Args[0].ToString();
            this.Properties["ArbitraryArgName"] = e.Args[0];
        }
        base.OnStartup(e);
    }

In MainWindow.xaml.cs

InitializeComponent();

        if (Application.Current.Properties["ArbitraryArgName"] != null)
        {

            string fname = Application.Current.Properties["ArbitraryArgName"].ToString();

            // Act on the file...
        }