find and replace values in cell array

I have a cell array like this: [...

0

129

8...2...3...4

6...4

0

I just want to find and replace specific values, but I can't use the ordinary function because the cells are different lengths. I need to replace many specific values at the same time and there is no general function about how values are replaced. However, sometimes sever开发者_运维问答al input values should be replaced by the same output.

so I want to say

for values 1:129

'if 0, then 9'

'elseif 1 then 50'

'elseif 2 or 3 or 4 then 61' etc...up to 129

where these rules are applied to the entire array.

I've tried to work it out myself, but still getting nowhere. Please help!

---

Since your values appear to span the range 0 to 129, one solution is to add one to these values (so they span the range 1 to 130) and use them as indices into a vector of replacement values. Then you can apply this operation to each cell using the function CELLFUN. For example:

>> C = {0, 129, [8 2 3 4], [6 4], 0};  %# The sample cell array you give above
>> replacement = [9 50 61 61 61 100.*ones(1,125)];  %# A 1-by-130 array of
                                                    %# replacement values (I
                                                    %# added 125 dummy values)
>> C = cellfun(@(v) {replacement(v+1)},C);  %# Perform the replacement
>> C{:}  %# Display the contents of C
ans =
     9

ans =
   100

ans =
   100    61    61    61

ans =
   100    61

ans =
     9