Redirecting the output of program which itself is an argument

Let me present the scenario first with the command which is not working under linux bash environment.

$ timed-run prog1 1>/dev/null 开发者_Python百科2>out.tmp

Here in the above case I want to redirect the output of program 'prog1' to /dev/null and out.tmp file. But this command is redirecting the output (if any) of timed-run to out.tmp.

Any help will be appreciated.

---

From a simple example, I experience exactly the opposite.

$ time ls 1> foo 2> bar

real    0m0.002s
user    0m0.004s
sys     0m0.000s
$ more foo
<show files>
$ more bar
<empty>
$

The output of ls is redirected, and the output of time is not!

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The problem here is in timed-run not in bash. If you run the same command replacing timed-run with the standard time command this works as you expect. Mainly timed run needs to run the arguments of prog1 through the shell again. If it is a shell script you can do this with the eval command. For example:

#!/bin/sh

echo here is some output
echo $*
eval $*

now run

timed-run prog1 '1>/dev/null' '2>output.tmp'

---

How about using sh -c 'cmd' like so:

    time -p sh -c 'ls -l xcvb 1>/dev/null 2>out.tmp'
    time -p sh -c 'exec 0</dev/null 1>/dev/null 2>out.tmp; ls -l xcvb'

    # in out.tmp:
    # ls: xcvb: No such file or directory