The following 开发者_StackOverflow中文版code
for h in hits:
urls.append(h['url'])
result = db.Blob(urlfetch.Fetch(h['url']).content)
model.image = result
returns the error
cannot concatenate 'str' and 'NoneType' objects.
Use some debug printing to find out if urlfetch.Fetch(h['url']).content
is even returning anything. Based on the error, the result is None
and db.Blob()
is expecting the result to be a string.
If so, plan accordingly by checking the value of content
before trying to apply it. And maybe a little error tracking for good measure?
Here's a simple example:
errors = []
for h in hits:
urls.append(h['url'])
content = urlfetch.Fetch(h['url']).content
if content is not None:
result = db.Blob(urlfetch.Fetch(h['url']).content)
else:
print 'No content for', h['url']
errors.append(h)
continue
model.image = result
I see concatenation only on this line:
urls.append(h['url'])
judging by error: 'String' would be urls, and 'NoneType' would be h['url'] Most likely h['url'] is empty. Make sure of this by printing it to console.
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