Here is my code:
path = wsdlPath;
S开发者_JS百科AXParserFactory saxfac = SAXParserFactory.newInstance();
saxfac.setNamespaceAware(true);
saxfac.setXIncludeAware(true);
saxfac.setValidating(false);
SAXParser saxParser = saxfac.newSAXParser();
saxParser.parse(wsdlPath, this);
After Setting setNamespaceAware=true
, I can't get the xmlns:XXX
attributes in parameter attributes
of method public void startElement(String uri, String localName, String qName, Attributes attributes)
.
for the following node:
<definitions name="Service1"
targetNamespace="http://www.test.com/service"
xmlns="http://schemas.xmlsoap.org/wsdl/"
xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/"
xmlns:mime="http://schemas.xmlsoap.org/wsdl/mime/"
xmlns:http="http://schemas.xmlsoap.org/wsdl/http/"
xmlns:tns="http://www.test.com/">
I just get name
and targetNamespace
attribute. xmlns
, xmlns:wsdl
, xmlns:mime
, xmlns:http
and xmlns:tns
are in the attributes
parameter. But they are not accessible.
Is there any way to use setNamespaceAware=true
and get all attributes of a node?
When your XML parser is XML Namespace aware, then you should not need access to those properties, as they only define the short names for namespaces used in your XML.
In that case you always refer to the name spaces using their full name (e.g. http://schemas.xmlsoap.org/wsdl/
) and can ignore what short name they are aliased to in the XML (e.g. wsdl
).
The fact that SAX doesn't provide those values is documented on the Attributes
class:
It will [...] not contain attributes used as Namespace declarations (
xmlns*
) unless thehttp://xml.org/sax/features/namespace-prefixes
feature is set totrue
(it isfalse
by default).
So using saxfac.setFeature("http://xml.org/sax/features/namespace-prefixes", true)
should help you get to those values.
The standard way to get the namespace declarations is from the startPrefixMapping event:
- http://download.oracle.com/javase/6/docs/api/org/xml/sax/helpers/DefaultHandler.html#startPrefixMapping(java.lang.String,%20java.lang.String)
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