class c{
public $myV = &$_GET;
}
it 开发者_JAVA技巧gives me error :(
if i do a plain simple:
$myV = &$_GET;
it works
You cannot even do this:
public $x = $y;
From the manual:
This declaration may include an initialization, but this initialization must be a constant value--that is, it must be able to be evaluated at compile time and must not depend on run-time information in order to be evaluated.
To get around this, just set it in the __construct
function.
public function __construct()
{
$this->myV = &$_GET;
}
... but this initialization must be a constant value--that is, it must be able to be evaluated at compile time and must not depend on run-time information in order to be evaluated.
from php.net : Properties
You can define this dependency in a constructor though.
Try this:
class c {
public $myV;
function c() {
$this->myV = &$_GET;
}
}
You cannot assign variables to fields before a class is instantiated. This way, your variable will be set when an object is made from your class.
You can achieve a similar effect like:
class c{
public $myV;
function __construct() { $this->myV = &$_GET; }
}
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