Query to check if field exists and then return the result set

I dont know how can i explain it, may be this example garbage query can help.

SELECT if_exists(Fieldname) * FROM my table name

I am trying to select all the rows of the database only if Fieldname field is present.

Can yo开发者_如何转开发u help me out

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SHOW columns from `yourtable` where field='yourfield'

You will get a empty rows, if you dont have that field in that table.

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The following code in plain PHP should work fine:

$chkcol = mysql_query("SELECT * FROM `table_name` LIMIT 1"); 
$mycol = mysql_fetch_array($chkcol); 
if(isset($mycol['column_name'])) 
  $results = mysql_query("SELECT * FROM `table_name`");
else
  $results = false;

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IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = ‘you_table_name’ AND COLUMN_NAME = ‘FIELDNAME’)
 BEGIN
    select fieldname from your_table_name
 END

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You can use the SHOW COLUMNS expression.

Also i found this solution: http://snippets.dzone.com/posts/show/4663

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You need something like this. Sorry, cannot test if the syntax is OK though.

SELECT * FROM table WHERE EXISTS (SELECT * FROM INFORMATION_SCHEMA.COLUMNS WHERE table_name=table AND column_name=column)

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Thats a query I used: it returns no column, if the column doesn't exist. It shouldn't be much work to change it, for you needs.

SET @VAR_SQL := Concat('SELECT first_row',CONCAT(IFNULL((SELECT CONCAT(',',COLUMN_NAME) FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = 'my_table' 
AND COLUMN_NAME = 'my_column'),'')),' FROM my_table;');
PREPARE QUERY_STATEMENT FROM @VAR_SQL;
EXECUTE QUERY_STATEMENT;