How do I convert an array of strings to a array of unique values?

I开发者_运维百科n Java, how do I convert an array of strings to a array of unique values?

If I have this array of Strings:

String[] test = {"1","1","1","2"}

And I want to end up with:

String[] uq = {"1","2"}

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Quick but somewhat inefficient way would be:

Set<String> temp = new HashSet<String>(Arrays.asList(test));
String[] uq = temp.toArray(new String[temp.size()]);

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If you're going with the HashSet-approach (which seems pretty handy) you should use a LinkedHashSet instead of a HashSet if you want to maintain the array's order!

Set<String> temp = new LinkedHashSet<String>( Arrays.asList( array ) );
String[] result = temp.toArray( new String[temp.size()] );

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An alternative to the HashSet approach would be to:

1. Sort the input array

2. Count the number of non-duplicate values in the sorted array

3. Allocate the output array

4. Iterate over the sorted array, copying the non-duplicate values to it.

The HashSet approach is O(N) on average assuming that 1) you preallocate the HashSet with the right size and 2) the (non-duplicate) values in the input array hash roughly evenly. (But if the value hashing is pathological, the worst case is O(N**2) !)

The sorting approach is O(NlogN) on average.

The HashSet approach takes more memory on average.

If you are doing this infrequently OR for really large "well behaved" input arrays, the HashSet approach is probably better. Otherwise, it could be a toss-up which approach is better.

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String[] test = {"1","1","1","2"};
java.util.Set result = new java.util.HashSet(java.util.Arrays.asList(test));
System.out.println(result);

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I tried all the answers on this page and none worked as-is. So, here is how I solved it, inspired by the answers from Taig and akuhn :

import groovy.io.*;
def arr = ["5", "5", "7", "6", "7", "8", "0"]
List<String> uniqueList = new ArrayList<String>( 
         new LinkedHashSet<String>( arr.asList() ).sort() );
System.out.println( uniqueList )

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An easy way is to create a set, add each element in the array to it, and then convert the set to an array.

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List list = Arrays.asList(test);
Set set = new HashSet(list);

String[] uq = set.toArray();

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Just found a nicer way in Java 8 :

Arrays.stream(aList).distinct().toArray(String[]::new)

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here is my solution:

int[] A = {2, 1, 2, 0, 1};

Arrays.sort(A);

ArrayList<Integer> B = new ArrayList<Integer>();

for (int i = 0; i < A.length; i++) {
 if (i == A.length-1) {
    B.add(A[i]);
 }
 else if (A[i] != A[i+1]) {
    B.add(A[i]);
 }
}

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String[] getDistinctElementsArray(String[] arr){

    StringBuilder distStrings = new StringBuilder();
    distStrings.append(arr[0] + " ");
    for(int i=1;i<arr.length;i++){
        if( arr[i].equals(arr[i-1])){}
        else{
            distStrings.append(arr[i] + " ");
        }
    }
    return distStrings.toString().split(" ");
}