I have array which I read from excel (using ParseExcel) using the following code:
workbook = Spreadsheet::ParseExcel.parse("test.xls")
rows = workbook.worksheet(1).map() { |r开发者_开发知识库| r }.compact
grid = rows.map() { |r| r.map() { |c| c.to_s('latin1') unless c.nil?}.compact rescue nil }
grid.sort_by { |k| k[2]}
test.xls has lots of rows and 6 columns. The code above sort by column 3.
I would like to output rows in array "grid" to many text file like this: - After sorting, I want to print out all the rows where column 3 have the same value into one file and so on for a different file for other same value in column3.
Hope I explain this right. Thanks for any help/tips.
ps. I search through most posting on this site but could not find any solution.
instead of using your above code, I made a test 100-row array, each row containing a 6-element array.
You pass in the array, and the column number you want matched, and this method prints into separate files rows that have the same nth element.
Since I used integers, I used the nth element of each row as the filename. You could use a counter, or the md5 of the element, or something like that, if your nth element does not make a good filename.
a = []
100.times do
b = []
6.times do
b.push rand(10)
end
a.push(b)
end
def print_files(a, column)
h = Hash.new
a.each do |element|
h[element[2]] ? (h[element[column]] = h[element[column]].push(element)) : (h[element[column]] = [element])
end
h.each do |k, v|
File.open("output/" + k.to_s, 'w') do |f|
v.each do |line|
f.puts line.join(", ")
end
end
end
end
print_files(a, 2)
Here is the same code using blocks instead of do .. end:
a = Array.new
100.times{b = Array.new;6.times{b.push rand(10)};a.push(b)}
def print_files(a, column)
h = Hash.new
a.each{|element| h[element[2]] ? (h[element[column]] = h[element[column]].push(element)) : (h[element[column]] = [element])}
h.map{|k, v| File.open("output/" + k.to_s, 'w'){|f| v.map{|line| f.puts line.join(", ")}}}
end
print_files(a, 2)
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