I'm trying to transfer the following URL validation function from my PHP code to my javascript code:
this.v开发者_JAVA技巧alidate_url = function(field)
{
var pattern = new RegExp("^((ht|f)tp(s?)\:\/\/|~/|/)?([\w]+:\w+@)?([a-zA-Z]{1}([\w\-]+\.)+([\w]{2,5}))(:[\d]{1,5})?((/?\w+/)+|/?)(\w+\.[\w]{3,4})?((\?\w+=\w+)?(&\w+=\w+)*)?");
var val = $("#" + field).val();
return pattern.test(val);
}
And this gives me the error:
invalid quantifier ?w+=w+)?(&w+=w+)*)?
How can I fix this?
You either need to escape the backslashes within the string declaration:
var pattern = new RegExp("^((ht|f)tp(s?)://|~/|/)?(\\w+:\\w+@)?([a-zA-Z]{1}([\\w-]+\\.)+(\\w{2,5}))(:\\d{1,5})?((/?\\w+/)+|/?)(\\w+\\.\\w{3,4})?((\\?\\w+=\\w+)?(&\\w+=\\w+)*)?");
Or you use the regular expression literal syntax /
expr
/
flags
:
var pattern = /^((ht|f)tp(s?):\/\/|~\/|\/)?(\w+:\w+@)?([a-zA-Z]{1}([\w-]+\.)+(\w{2,5}))(:\d{1,5})?((\/?\w+\/)+|\/?)(\w+\.\w{3,4})?((\?\w+=\w+)?(&\w+=\w+)*)?/;
You should also try to use non-capturing groups (?:
expr
)
where you don’t need to reference the match of that groups.
Since backslash is an escaping character in JavaScript, you'll have to escape that to write it in a string:
var pattern = new RegExp("^((ht|f)tp(s?)\\:\\/\\/|~/|/)?([\\w]+:\\w+@)?([a-zA-Z]{1}([\\w\\-]+\\.)+([\\w]{2,5}))(:[\\d]{1,5})?((/?\\w+/)+|/?)(\\w+\\.[\\w]{3,4})?((\\?\\w+=\\w+)?(&\\w+=\\w+)*)?");
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