bash debugging using set -u

I have a bash sourcedbash.sh sourced in another bash main code main.sh开发者_如何学C.

Running main.sh with the "set -u" option, I'm getting an error than I can't figure out :

Error /sourced_bash.sh : line xx : variable without link  

main.sh

. sourced_bash.sh
my_function $foomain 1

sourcedbash.sh

function my_function(){
   local foo=$1
   local bar=$2
   if [[ 1 -eq $bar ]];then # <= this is LINE xx generating the error
        # ... dothis
        return 1
   elif [[ 0 -eq $bar ]];then
        # ... dothat
        return 0
   fi
}

Looked into the man pages and reading "my friend" w/o a frank success.

I'd need to understand why "set -u" implies the main.sh program aborption and how to get rid of this error (Debian Lenny).

Thx in advance

---

Since you are doing string comparison, you need to use quotes and ==. Try changing to:

   if [[ "1" == "$bar" ]] || [[ "true" == "$bar" ]];then

Update:

What is $foomain? Has it been set?

set -u makes Bash check whether you have initialised all your variables. If you haven't, Bash will throw an error about unbound variables.