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Repeating Events on the "nth" Weekday of Every Month

开发者 https://www.devze.com 2023-02-18 22:28 出处:网络
I\'ve looked at at least 2 dozen topics about this and haven\'t really found a good answer yet, so I come to you to ask once again for answers regarding the dreaded topic of Repeating Events.

I've looked at at least 2 dozen topics about this and haven't really found a good answer yet, so I come to you to ask once again for answers regarding the dreaded topic of Repeating Events.

I've got Daily, Weekly, Monthly, and Yearly repeats working out fine for now (I still need to revamp the system with Exception events and whatnot, but it works for the time being). But, we want to be able to add the ability to repeat events on the (1st,2nd,3rd,4th,5th) [Sun|Mon|Tue|Wed|Thu|Fri|Sat] of every month, 开发者_StackOverflow中文版every other month, and every three months.

Now, if I can just understand the logic for the every month, I can figure out the every other month and the every three months.

Here's a bit of what I have so far (note: I'm not saying I have the best way of doing it or anything, but the system is one we update very slowly over time when we aren't busy with other projects, so I make the code more efficient as I have the time).

First I get the starting and ending dates formatted for date calculations:

$ending = $_POST['end_month'] . "/" . $_POST['end_day'] . "/" . substr($_POST['end_year'], 2, 2);
$starting = $_POST['month'] . "/" . $_POST['day'] . "/" . substr($_POST['year'], 2, 2);

Then I get the difference between those two to know how many times to repeat using a function I'm fairly certain I found on here some time ago and dividing that amount by 28 days to get just about how many TIMES it needs to repeat so that there is one a month:

$repeat_number = date_diff($starting, $ending) / 28;
//find the difference in DAYS between the two dates
function date_diff($old_date, $new_date) {
$offset = strtotime($new_date) - strtotime($old_date);
return $offset/60/60/24;
}

Then I add the (1st,2nd,etc...) part to the [Sun|Mon|etc...] part to figure out what they are looking for giving me somehthing like 'first Sunday' :

$find = $_POST['custom_number']. ' ' . $_POST['custom_day'];

Then I use a loop that runs the number of times this needs to repeat (the $repeat_number from above):

for($m = 0; $m <= $repeat_number; $m++) {
if($m == 0) {
     $month = date('F', substr($starting,0,2));
} else {
     $month = date('F', strtotime($month . ' + ' . $m . ' months'));
}
$repeat_date = strtotime($find . ' in ' . $month);
}

Now, I'm aware this code doesn't work, I at one time did have code that turned up the correct month and year for the repeat, but wouldn't necessarily find the first tuesday or whatever it was that was being looked for.

If anyone could point me back in the right direction, it would be most appreciated. I've been lurking in the community for some time now, just started trying to actively participate recently.

Thanks in advance for any input or advice you can provide.


Here's a possible alternative for you. strtotime is powerful, and the syntax includes really useful bits like comprehensive relative time and date wording.

You can use it to generate the first through Nth specific weekdays of a specific month by using the format " of ". Here's an example using date_create to invoke a DateTime object, but regular old strtotime works the same way:

php > $d = date_create('Last Friday of March 2011'); if($d instanceof DateTime) echo $d->format('l F d Y H:i:s');
Friday March 25 2011 00:00:00
php > $d = date_create('First Friday of March 2011'); if($d instanceof DateTime) echo $d->format('l F d Y H:i:s');
Friday March 04 2011 00:00:00
php > $d = date_create('First Sunday of March 2011'); if($d instanceof DateTime) echo $d->format('l F d Y H:i:s');
Sunday March 06 2011 00:00:00
php > $d = date_create('Fourth Sunday of March 2011'); if($d instanceof DateTime) echo $d->format('l F d Y H:i:s');
Sunday March 27 2011 00:00:00
php > $d = date_create('Last Sunday of March 2011'); if($d instanceof DateTime) echo $d->format('l F d Y H:i:s');
Sunday March 27 2011 00:00:00

It will also overflow the month, if you ask for an invalid one:

php > $d = date_create('Ninth Sunday of March 2011'); if($d instanceof DateTime) echo $d->format('l F d Y H:i:s');
Sunday May 01 2011 00:00:00

Note that it only works with the ordinal number wording. You can't pass "1st" or "3rd", unfortunately.

Once you use this to grab the proper Nth weekday, you can then simply add the number of needed weekdays to skip (7 for one week, 14 for two, 21 for three, etc) as required until the designated end date or designated number of weeks has passed. Once again, strtotime to the rescue, using the second argument to chain together relativeness:

php > echo date('l F d Y H:i:s', strtotime('+14 days', strtotime('First Thursday of March 2011')));
Thursday March 17 2011 00:00:00

(My local copy also accepted '+14 days First Thursday of March 2011', but that felt kind of weird.)


I have a more simple method, although it may seem hack-ish.

What we can do is take the start date, and infer it's "n" value from it by taking the ceiling of its day divided by 7.

For example, if your start date is the 18th, we divide by 7 and take the ceiling to infer that it is the 3rd "whatever-day" of the month.

From there we can simply repeatedly add 7 days to this to get a new date, and whenever the new date's ceilinged 7-quotient is 3, we've hit the next "nth whatever-day" of the month.

Some code can be seen below:

$day_nth = ceil(date("j", strtotime($date))/7);
for ($i = 0; $i < $number_of_repeats; $i++) {

    while (ceil(date("j", strtotime($date))/7) != $day_nth)
        $date = date("Y-m-d", strtotime("+7 days", strtotime($date)));

    /* Add your event, or whatever */

    /* Now we increment date by 7 days before the loop starts again,
    ** otherwise the while loop would never execute and we'd just be
    ** adding to the same date repeatedly. */
    $date = date("Y-m-d", strtotime("+7 days", strtotime($date)));
}

What's nice about this method is that we don't even have to concern ourselves with which day of the week we're dealing with. We just infer everything from the start date and away we go.


I make it like that:

            //$typeOfDate = 0;
            $typeOfDate = 1;
            $day = strtotime("2013-02-01");
            $to = strtotime(date("Y-m-d", $day) . " +6 month");

            if ($typeOfDate == 0) { //use the same day (number) of the month
                $dateArray[] = date("Y-m-d", $day);
                $event_day_number = date("d", $day);
                while ($day <= $to) {
                    $nextMonth = date("m", get_x_months_to_the_future($day));
                    $day = strtotime(date("Y-" . $nextMonth . "-d", $day));
                    $dateArray[] = date("Y-m-d", $day);
                }
            }

            if ($typeOfDate == 0) { //use the same day (like friday) of the month
                $dateArray[] = date("Y-m-d", $day);
                $monthEvent = date("m", $day);
                $day = strtotime(date("Y-m-d", $day) . " +4 weeks");
                $newMonthEvent = date("m", $day);
                if ($monthEvent == $newMonthEvent) {
                    $day = strtotime(date("Y-m-d", $day) . " +7 days");
                }
                while ($day <= $to) {
                    $dateArray[] = date("Y-m-d", $day);
                    $monthEvent = date("m", $day);
                    $day = strtotime(date("Y-m-d", $day) . " +4 weeks");
                    $newMonthEvent = date("m", $day);
                    if ($monthEvent == $newMonthEvent) {
                        $day = strtotime(date("Y-m-d", $day) . " +7 days");
                    }
                }
            }
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