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Search special-string in a text and replace with contents from array

开发者 https://www.devze.com 2023-02-18 18:39 出处:网络
Consider this text $text = \'bla bla bla bla (=abc) bla bla bla bla (=var.var)\'; There are 2 special values there (=abc) and (=var.var)

Consider this text

$text = 'bla bla bla bla (=abc) bla bla bla bla (=var.var)';

There are 2 special values there (=abc) and (=var.var)

I need to replace them with values from this array:

$array['abc']='word1';
$array['var.var']='word2';

Basically inside the pattern is (=[a-z.]+) (chars a-z and dot).

Result i need: bla bla bla bla *word1* bla bla bla bla *word2* (without *)

I tried this with no luck

preg_replace('/\(=([a-z\.]+)\)/',"$array['\\1'开发者_Python百科]",$text);

Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in D:\net\test\index.php on line 9


Since you the replacement string cannot be derived from the contents of the match (it involves external data in $array, you need to use preg_replace_callback.

This example assumes PHP 5.3 for anonymous functions, but you can do the same (in a slightly more cumbersome way) with create_function in any PHP version.

$text = 'bla bla bla bla (=abc) bla bla bla bla (=var.var)';
$array['abc']='word1';
$array['var.var']='word2';

$result = preg_replace_callback(
            '/\(=([a-z\.]+)\)/', 
            function($matches) use($array) { return $array[$matches[1]]; },
            $text);


The < PHP 5.3 solution :)

$text = 'bla bla bla bla (=abc) bla bla bla bla (=var.var)';

$text = preg_replace_callback('/\(=([\w.]+?)\)/', 'processMatches', $text);

function processMatches($matches) {
    $array = array();
    $array['abc']='word1';
    $array['var.var']='word2';
    return isset($array[$matches[1]]) ? $array[$matches[1]] : '';
}

var_dump($text); // string(43) "bla bla bla bla word1 bla bla bla bla word2"

CodePad.

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