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PostgreSQL: SQL script to get a list of all tables that have a particular column as foreign key

开发者 https://www.devze.com 2023-02-18 16:45 出处:网络
I\'m using PostgreSQL and I\'m trying to list all the tables that have a particular column from a table as a foreign-key/referenc开发者_高级运维e. Can this be done? I\'m sure this information is store

I'm using PostgreSQL and I'm trying to list all the tables that have a particular column from a table as a foreign-key/referenc开发者_高级运维e. Can this be done? I'm sure this information is stored somewhere in information_schema but I have no idea how to start querying it.


SELECT
    r.table_name
FROM information_schema.constraint_column_usage       u
INNER JOIN information_schema.referential_constraints fk
           ON u.constraint_catalog = fk.unique_constraint_catalog
               AND u.constraint_schema = fk.unique_constraint_schema
               AND u.constraint_name = fk.unique_constraint_name
INNER JOIN information_schema.key_column_usage        r
           ON r.constraint_catalog = fk.constraint_catalog
               AND r.constraint_schema = fk.constraint_schema
               AND r.constraint_name = fk.constraint_name
WHERE
    u.column_name = 'id' AND
    u.table_catalog = 'db_name' AND
    u.table_schema = 'public' AND
    u.table_name = 'table_a'

This uses the full catalog/schema/name triplet to identify a db table from all 3 information_schema views. You can drop one or two as required.

The query lists all tables that have a foreign key constraint against the column 'a' in table 'd'


The other solutions are not guaranteed to work in postgresql, as the constraint_name is not guaranteed to be unique; thus you will get false positives. PostgreSQL used to name constraints silly things like '$1', and if you've got an old database you've been maintaining through upgrades, you likely still have some of those around.

Since this question was targeted AT PostgreSQL and that is what you are using, then you can query the internal postgres tables pg_class and pg_attribute to get a more accurate result.

NOTE: FKs can be on multiple columns, thus the referencing column (attnum of pg_attribute) is an ARRAY, which is the reason for using array_agg in the answer.

The only thing you need plug in is the TARGET_TABLE_NAME:

select 
  (select r.relname from pg_class r where r.oid = c.conrelid) as table, 
  (select array_agg(attname) from pg_attribute 
   where attrelid = c.conrelid and ARRAY[attnum] <@ c.conkey) as col, 
  (select r.relname from pg_class r where r.oid = c.confrelid) as ftable 
from pg_constraint c 
where c.confrelid = (select oid from pg_class where relname = 'TARGET_TABLE_NAME');

If you want to go the other way (list all of the things a specific table refers to), then just change the last line to:

where c.conrelid = (select oid from pg_class where relname = 'TARGET_TABLE_NAME');

Oh, and since the actual question was to target a specific column, you can specify the column name with this one:

select (select r.relname from pg_class r where r.oid = c.conrelid) as table, 
       (select array_agg(attname) from pg_attribute 
        where attrelid = c.conrelid and ARRAY[attnum] <@ c.conkey) as col, 
       (select r.relname from pg_class r where r.oid = c.confrelid) as ftable 
from pg_constraint c 
where c.confrelid = (select oid from pg_class where relname = 'TARGET_TABLE_NAME') and 
      c.confkey @> (select array_agg(attnum) from pg_attribute 
                    where attname = 'TARGET_COLUMN_NAME' and attrelid = c.confrelid);


This query requires only the referenced table name and column name, and produces a result set containing both sides of the foreign key.

select confrelid::regclass, af.attname as fcol,
       conrelid::regclass, a.attname as col
from pg_attribute af, pg_attribute a,
  (select conrelid,confrelid,conkey[i] as conkey, confkey[i] as confkey
   from (select conrelid,confrelid,conkey,confkey,
                generate_series(1,array_upper(conkey,1)) as i
         from pg_constraint where contype = 'f') ss) ss2
where af.attnum = confkey and af.attrelid = confrelid and
      a.attnum = conkey and a.attrelid = conrelid 
  AND confrelid::regclass = 'my_table'::regclass AND af.attname = 'my_referenced_column';

Example result set:

confrelid |         fcol         |   conrelid    |     col
----------+----------------------+---------------+-------------
 my_table | my_referenced_column | some_relation | source_type
 my_table | my_referenced_column | some_feature  | source_type

All credit to Lane and Krogh at the PostgreSQL forum.


Personally, I prefer to query based on the referenced unique constraint rather than the column. That would look something like this:

SELECT rc.constraint_catalog,
       rc.constraint_schema||'.'||tc.table_name AS table_name,
       kcu.column_name,
       match_option,
       update_rule,
       delete_rule
FROM information_schema.referential_constraints AS rc 
    JOIN information_schema.table_constraints AS tc USING(constraint_catalog,constraint_schema,constraint_name)
    JOIN information_schema.key_column_usage AS kcu USING(constraint_catalog,constraint_schema,constraint_name)
WHERE unique_constraint_catalog='catalog'
    AND unique_constraint_schema='schema'
    AND unique_constraint_name='constraint name';

Here is a version that allows querying by column name:

SELECT rc.constraint_catalog,
       rc.constraint_schema||'.'||tc.table_name AS table_name,
       kcu.column_name,
       match_option,
       update_rule,
       delete_rule
FROM information_schema.referential_constraints AS rc
    JOIN information_schema.table_constraints AS tc USING(constraint_catalog,constraint_schema,constraint_name)
    JOIN information_schema.key_column_usage AS kcu USING(constraint_catalog,constraint_schema,constraint_name)
    JOIN information_schema.key_column_usage AS ccu ON(ccu.constraint_catalog=rc.unique_constraint_catalog AND ccu.constraint_schema=rc.unique_constraint_schema AND ccu.constraint_name=rc.unique_constraint_name)
WHERE ccu.table_catalog='catalog'
    AND ccu.table_schema='schema'
    AND ccu.table_name='name'
    AND ccu.column_name='column';


SELECT
  main_table.table_name            AS main_table_table_name,
  main_table.column_name           AS main_table_column_name,
  main_table.constraint_name       AS main_table_constraint_name,
  info_other_table.table_name      AS info_other_table_table_name,
  info_other_table.constraint_name AS info_other_table_constraint_name,
  info_other_table.column_name     AS info_other_table_column_name
FROM INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE main_table
  INNER JOIN INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS other_table
    ON other_table.unique_constraint_name = main_table.constraint_name
  INNER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE info_other_table
    ON info_other_table.constraint_name = other_table.constraint_name
WHERE main_table.table_name = 'MAIN_TABLE_NAME';


A simple request for recovered the names of foreign key as well as the names of the tables:

SELECT CONSTRAINT_NAME, table_name
FROM
   information_schema.table_constraints 
WHERE table_schema='public' and constraint_type='FOREIGN KEY'


If you use the psql client, you can simply issue the \d table_name command to see which tables reference the given table. From the linked documentation page:

\d[S+] [ pattern ]

For each relation (table, view, materialized view, index, sequence, or foreign table) or composite type matching the pattern, show all columns, their types, the tablespace (if not the default) and any special attributes such as NOT NULL or defaults. Associated indexes, constraints, rules, and triggers are also shown. For foreign tables, the associated foreign server is shown as well.


Table constraints can include multiple columns. The trick to getting this right is to join each column by their constraint ordinal positions. If you don't join correctly your script will blow up with duplicate rows

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