i used this link to build a basic jqgrid: http://haacked.com/archive/2009/04/14/using-jquery-grid-with-asp.net-mvc.aspx
this my code:
<script type="text/javascript">
jQuery(document).ready(function () {
jQuery("#list").jqGrid({
url: '/Home/GridData/',
datatype: 'json',
mtype: 'GET',
colNames: ['ProductID', 'ProductName'],
colModel: [
{ name: 'ProductID', index: 'ProductID', width: 40, align: 'left' },
{ name: 'ProductName', index: 'ProductName', width: 40, align: 'left'}],
pager: jQuery('#pager'),
rowNum: 10,
rowList: [5, 10, 20, 50],
sortname: 'Id',
sortorder: "desc",
viewrecords: true,
imgpath: '/scripts/th开发者_高级运维emes/coffee/images',
caption: 'My first grid'
});
});
public ActionResult GridData(string sidx, string sord, int page, int rows)
{
List<Product> listProducts = new List<Product>(){new Product(){ProductName = "koekies",ProductID = 1},
new Product(){ProductName = "snoepjes",ProductID = 2}};
return Json(listProducts, JsonRequestBehavior.AllowGet);
}
Did you read the entire post that you linked? His returning json looks a lot different than what you are returning.
public ActionResult GridData(string sidx, string sord, int page, int rows) {
var jsonData = new {
total = 1, // we'll implement later
page = page,
records = 3, // implement later
rows = new[]{
new {id = 1, cell = new[] {"1", "-7", "Is this a good question?"}},
new {id = 2, cell = new[] {"2", "15", "Is this a blatant ripoff?"}},
new {id = 3, cell = new[] {"3", "23", "Why is the sky blue?"}}
}
};
return Json(jsonData, JsonRequestBehavior.AllowGet);
}
That id field is important, jsgrid likes to know the row number that you are adding.
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