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How can I insert a tab character with sed on OS X?

开发者 https://www.devze.com 2023-02-18 07:27 出处:网络
I have tried: echo -e \"开发者_运维知识库egg\\t\\t\\t salad\" | sed -E \'s/[[:blank:]]+/\\t/g\'

I have tried:

echo -e "开发者_运维知识库egg\t  \t\t salad" | sed -E 's/[[:blank:]]+/\t/g'

Which results in:

eggtsalad

And...

echo -e "egg\t  \t\t salad" | sed -E 's/[[:blank:]]+/\\t/g'

Which results in:

egg\tsalad

What I would like:

egg salad


Try: Ctrl+V and then press Tab.


Use ANSI-C style quoting: $'string'

sed $'s/foo/\t/'

So in your example, simply add a $:

echo -e "egg\t  \t\t salad" | sed -E $'s/[[:blank:]]+/\t/g'


OSX's sed only understands \t in the pattern, not in the replacement doesn't understand \t at all, since it's essentially the ancient 4.2BSD sed left over from 1982 or thenabouts. Use a literal tab (which in bash and vim is Ctrl+V, Tab), or install GNU coreutils to get a more reasonable sed.


Another option is to use $(printf '\t') to insert a tab, e.g.:

echo -e "egg\t  \t\t salad" | sed -E "s/[[:blank:]]+/$(printf '\t')/g"


try awk

echo -e "egg\t  \t\t salad" | awk '{gsub(/[[:blank:]]+/,"\t");print}'


A workaround for tab on osx is to use "\ ", an escape char followed by four spaces.

If you are trying to find the last instance of a pattern, say a " })};" and insert a file on a newline after that pattern, your sed command on osx would look like this:

sed -i '' -e $'/^\    \})};.*$/ r fileWithTextIWantToInsert' FileIWantToChange

The markup makes it unclear: the escape char must be followed by four spaces in order for sed to register a tab character on osx.

The same trick works if the pattern you want to find is preceded by two spaces, and I imagine it will work for finding a pattern preceded by any number of spaces as well.

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