SELECT
PC_SL_ACNO, -- DB ITEM
SLNAME, -- ACCOUNT NAME:
S开发者_JS百科L_TOTAL_AMOUNT -- TOTAL AMOUNT:
FROM GLAS_PDC_CHEQUES
WHERE PC_COMP_CODE=:parameter.COMP_CODE
AND pc_bank_from = :block02.pb_bank_code
AND pc_due_date between :block01.date_from
AND :block01.date_to
AND nvl(pc_discd,'X') IN(‘X’, 'R')
GROUP BY
pc_comp_code, pc_sl_ldgr_code, pc_sl_acno
ORDER BY pc_sl_acno
ACCOUNT NAME:
BEGIN
SELECT COAD_PTY_FULL_NAME INTO :BLOCK03.SLNAME
FROM GLAS_PTY_ADDRESS,GLAS_SBLGR_MASTERS
WHERE SLMA_COMP_CODE = :PARAMETER.COMP_CODE
AND SLMA_ADDR_ID = COAD_ADDR_ID
AND SLMA_ADDR_TYPE = COAD_ADDR_TYPE
AND SLMA_ACNO = :BLOCK03.PC_SL_ACNO
AND SLMA_COMP_CODE = COAD_COMP_CODE;
EXCEPTION WHEN OTHERS THEN NULL;
END;
TOTAL AMOUNT:
BEGIN
SELECT SUM(PC_AMOUNT) INTO :SL_TOTAL_AMOUNT
FROM GLAS_PDC_CHEQUES
WHERE PC_DUE_DATE BETWEEN :BLOCK01.DATE_FROM AND :BLOCK01.DATE_TO
AND PC_BANK_FROM = :block02.PB_BANK_CODE
AND PC_SL_ACNO = :BLOCK03.PC_SL_ACNO
AND NVL(PC_DISCD,'X') = 'R'
AND PC_COMP_CODE = :PARAMETER.COMP_CODE;
EXCEPTION WHEN OTHERS THEN :block03.SL_TOTAL_AMOUNT := 0;
END;
How can I join the three tables?
You'll have to adjust depending on precisely what criteria and required fields you have for your query or queries.
SELECT
c.PC_SL_ACNO,
a.COAD_PTY_FULL_NAME,
SUM(c.PC_AMOUNT)
FROM
GLAS_PDC_CHEQUES c
LEFT JOIN
GLAS_SBLGR_MASTERS m
ON ( c.PC_SL_ACNO = m.SLMA_ACNO
AND c.PC_COMP_CODE = m.SLMA_COMP_CODE
)
LEFT JOIN
GLAS_PTY_ADDRESS a
ON ( m.SLMA_ADDR_ID = a.COAD_ADDR_ID
AND m.SLMA_COMP_CODE = a.COAD_COMP_CODE
AND m.SLMA_ADDR_TYPE = a.COAD_ADDR_TYPE
)
WHERE
c.PC_COMP_CODE = :PARAMETER.COMP_CODE
AND c.PC_SL_ACNO = :BLOCK03.PC_SL_ACNO
AND c.PC_BANK_FROM = :BLOCK02.PB_BANK_CODE
AND NVL(c.PC_DISCD,'X') IN (‘X’, 'R')
AND c.PC_DUE_DATE BETWEEN :BLOCK01.DATE_FROM AND :BLOCK01.DATE_TO
GROUP BY
c.PC_SL_ACNO, -- not sure which grouping exactly you need.
a.COAD_PTY_FULL_NAME
ORDER BY
c.PC_SL_ACNO
I notice that in the first query you have pc_comp_code
as a search criterion, and on the leading edge of your grouping - is that what you need?
This is a bit of an 'estimate' due to the enigmatic nature of your question!
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