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problem in passing parameters to url in android [duplicate]

开发者 https://www.devze.com 2023-02-17 10:05 出处:网络
This question already has answers here: Closed 11 years ago. Possible Duplicate: passing parameters to url in android
This question already has answers here: Closed 11 years ago.

Possible Duplicate:

passing parameters to url in android

I have passed parameter to url in android.How can I know whether the value I have passed is sent to the url.Below is my java code

package com.xib;


import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.Reader;
import java.io.StringWriter;
import java.io.Writer;
import java.util.ArrayList;
import java.util.List;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
public class TestHttpPost extends Activity {


@Override
public void onCreate(Bundle savedInstanceState) 
{
    super.onCreate(savedInstanceState);
    postData();

}
public void postData() { 
    Log.d("hi", "value of array is ");

    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://services.mascus.com/api/mascusapi.asmx?op=OpenSession");


    try 
    {
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        nameValuePairs.add(new BasicNameValuePair("username", "xib"));
        nameValuePairs.add(new BasicNameValuePair("password", "efi99LKW"));

        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        Log.d("hi", "value of array is ");

        HttpResponse response = httpclient.execute(httppost);
        Log.e("hi", "value of array is ->"+convertStreamToString(response.getEntity().getContent()));

    } 
    catch (ClientProtocolException e) 
    {
        e.printStackTrace();
    } 
    catch (IOException e)
    {
       e.printStackTrace();

    }
} 
public String convertStreamToString(InputStream is)
throws IOException {
    /*
     * To convert the InputStream to String we use the
     * Reader.read(char[] buffer) method. We iterate until the
     * Reader return -1 which means there's no more data to
     * read. We use the StringWriter class to produce the string.
     */
    if (is != null)
    {
        Writer writer = new StringWriter();
      char[] buffer = new char[1024];
        try {
            Reader reader = new BufferedReader(new InputStreamReader(is, "UTF-8开发者_如何学Go"));
            int n;
            while ((n = reader.read(buffer)) != -1) {
                writer.write(buffer, 0, n);
            }
        } finally {
            is.close();
        }
        return writer.toString();
    } else {        
        return "";
    }
  }

}

Can anyone help me Thanks in advance Tushar


Just add this line

   String data = EntityUtils.toString(response.getEntity()); 
     System.out.println("Data..."+data);

after this line..

 httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

and check log.... u will get response from server..


   String link_push ="Your link"
DefaultHttpClient hc_push=new DefaultHttpClient();  
ResponseHandler <String> res_push=new BasicResponseHandler();  
HttpPost postMethod_push=new HttpPost(link_push);  
List<NameValuePair> nameValuePairs_push= new ArrayList<NameValuePair>(3);  
nameValuePairs_push.add(newBasicNameValuePair("city_id","0000")));    
   nameValuePairs_push.add(new BasicNameValuePair("user_id","value"));  
    postMethod_push.setEntity(new UrlEncodedFormEntity(nameValuePairs_push));
String response_push=hc_push.execute(postMethod_push,res_push);
Log.v("Response for Push Notification",""+response_push);

In these respones_push you will get the response from the server.. try this..

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