Is possible to drop the xsl: to XSL tags in XSL Stylesheets?

For example, could:

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<xsl:if test=''>

be typed as:

<if test=''>

Edit: Stylesheet has HTML and XML nodes within it.

Thanks, Ross

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Indeed you can do this, by defining the XSLT ("http://www.w3.org/1999/XSL/Transform") namespace as the default namespace:

 <stylesheet xmlns="http://www.w3.org/1999/XSL/Transform">
    ...
 </stylesheet>

The downside is that you then must use another prefix for your "domain" namespaces:

 <stylesheet xmlns="http://www.w3.org/1999/XSL/Transform" xmlns:foo="http://whatever" xmlns:html="http://www.w3.org/1999/xhtml">
    <template match="foo:bar">
       <html:form>
           ...
       </html:form>
    </template>
 </stylesheet>

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Sure you can, but combining @ysdx and @Jon's answers, beware that your XSLT processor needs to differentiate between XSLT elements and output elements. For example, the following stylesheet throws an error in Firefox:

<stylesheet version="1.0" xmlns="http://www.w3.org/1999/XSL/Transform">
    <template match="/">
        <!-- <b> is not a valid XSLT element -->
        <b><value-of select="'test'"/></b>
    </template>
</stylesheet>

Which means you need to qualify the names of output elements, like this:

<stylesheet version="1.0" 
         xmlns="http://www.w3.org/1999/XSL/Transform"
         xmlns:test="http://whatever">
    <template match="/">
        <test:b><value-of select="'test'"/></test:b>
    </template>
</stylesheet>

This can be problematic. You should stick to the conventional xsl prefix, unless you can think of a good reason not to.

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Don't think so. They differentiate between the "language" and any nodes that are intended for output.

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Yes.

But do note that this has nothing to do with XSLT itself but with XML Names. That's why there are differences between XML 1.0 and XML 1.1 usage.

As example, here you have some of my previus answers using this syntax:

using xml as xsl variable

XSLT multiple string replacement with recursion