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How to check whether element is in the array in java?

开发者 https://www.devze.com 2023-02-17 05:47 出处:网络
How to check whether element is in the array in java? int[] a = new int[5]; a[0] = 5; a[1] = 2; a[2] = 4;

How to check whether element is in the array in java?

        int[] a = new int[5];
        a[0] = 5;
        a[1] = 2;
        a[2] = 4;
        a[3] = 12;
        a[4] = 6;
        int k = 2;
        if (k in a) { // whats's wrong here?
            System.out.println("Yes");
        }
        else {
            System.out.println(开发者_JAVA技巧"No");
        }

Thanks!


The "foreach" syntax in java is:

for (int k : a) { // the ':' is your 'in'
  if(k == 2){ // you'll have to check for the value explicitly
    System.out.println("Yes");
  }
}


You have to do the search yourself. If the list were sorted, you could use java.util.arrays#binarySearch to do it for you.


What's wrong? The compiler should say you that there is no in keyword.

Normally you would use a loop here for searching. If you have many such checks for the same list, sort it and use binary search (using the methods in java.util.Arrays).


Instead of taking array you can use ArrayList. You can do the following

ArrayList list = new ArrayList();
list.add(5);
list.add(2);
list.add(4);
list.add(12);
list.add(6);
int k = 2;
if (list.contains(k) { 
    System.out.println("Yes");
}
else {
    System.out.println("No");
}


You will need to iterate over the array comparing each element until you find the one that you are looking for:

// assuming array a that you defined.
int k = 2;
for(int i = 0; i < a.length; i++)
{
    if(k == a[i])
    {
        System.out.println("Yes");
        break;
    }
}


If using java 1.5+

List<Integer> l1 = new ArrayList<Object>(); //build list 

for ( Integer i : l1 ) {  // java foreach operator 
  if ( i == test_value ) { 
      return true; 
  } 
} 
return false; 
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