I have a FileInputStream created using Context.openFileInput()
. I now want to convert the file into a byte array.
Unfortunately, I can't determine the size of the byte array required for FileInputStream.read(byte[])
. The available()
method doesn't work, and I can't create a File to check it's length using the specific pathname, probably because the path is inaccessible to non-root users.
I read about ByteArrayOutputStream
, and it seems to dynamically adjust the byte array size to fit, but I can't get how t开发者_JAVA百科o read from the FileInputStream
to write to the ByteArrayOutputStream
.
This should work.
InputStream is = Context.openFileInput(someFileName);
ByteArrayOutputStream bos = new ByteArrayOutputStream();
byte[] b = new byte[1024];
while ((int bytesRead = is.read(b)) != -1) {
bos.write(b, 0, bytesRead);
}
byte[] bytes = bos.toByteArray();
This is the easiest way
FileInputStream fis = openFileInput(fileName);
byte[] buffer = new byte[(int) fis.getChannel().size()];
fis.read(buffer);
You can pre-allocate the byte array using
int size = context.getFileStreamPath(filename).length();
This way, you will avoid allocating memory chunks every time your ByteArrayOutputStream
fills up.
For the method to work on any device and aplication you just need to replace:
InputStream is = Context.getContentResolver().openInputStream(yourFileURi);
This way you can encode external files as well.
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