Is there a way for java to convert int's to开发者_如何转开发 ascii symbols?
Do you want to convert int
s to char
s?:
int yourInt = 33;
char ch = (char) yourInt;
System.out.println(yourInt);
System.out.println(ch);
// Output:
// 33
// !
Or do you want to convert int
s to String
s?
int yourInt = 33;
String str = String.valueOf(yourInt);
Or what is it that you mean?
If you first convert the int to a char, you will have your ascii code.
For example:
int iAsciiValue = 9; // Currently just the number 9, but we want Tab character
// Put the tab character into a string
String strAsciiTab = Character.toString((char) iAsciiValue);
There are many ways to convert an int to ASCII (depending on your needs) but here is a way to convert each integer byte to an ASCII character:
private static String toASCII(int value) {
int length = 4;
StringBuilder builder = new StringBuilder(length);
for (int i = length - 1; i >= 0; i--) {
builder.append((char) ((value >> (8 * i)) & 0xFF));
}
return builder.toString();
}
For example, the ASCII text for "TEST" can be represented as the byte array:
byte[] test = new byte[] { (byte) 0x54, (byte) 0x45, (byte) 0x53, (byte) 0x54 };
Then you could do the following:
int value = ByteBuffer.wrap(test).getInt(); // 1413829460
System.out.println(toASCII(value)); // outputs "TEST"
...so this essentially converts the 4 bytes in a 32-bit integer to 4 separate ASCII characters (one character per byte).
You can convert a number to ASCII in java. example converting a number 1 (base is 10) to ASCII.
char k = Character.forDigit(1, 10);
System.out.println("Character: " + k);
System.out.println("Character: " + ((int) k));
Output:
Character: 1
Character: 49
In fact in the last answer String strAsciiTab = Character.toString((char) iAsciiValue); the essential part is (char)iAsciiValue which is doing the job (Character.toString useless)
Meaning the first answer was correct actually char ch = (char) yourInt;
if in yourint=49 (or 0x31), ch will be '1'
In Java, you really want to use Integer.toString to convert an integer to its corresponding String value. If you are dealing with just the digits 0-9, then you could use something like this:
private static final char[] DIGITS =
{'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
private static char getDigit(int digitValue) {
assertInRange(digitValue, 0, 9);
return DIGITS[digitValue];
}
Or, equivalently:
private static int ASCII_ZERO = 0x30;
private static char getDigit(int digitValue) {
assertInRange(digitValue, 0, 9);
return ((char) (digitValue + ASCII_ZERO));
}
The most simple way is using type casting:
public char toChar(int c) {
return (char)c;
}
tl;dr
Use Character#toString
, not char
.
String result = Character.toString( yourAsciiNumber ) ;
Ex:
Character.toString( 97 ) // LATIN SMALL LETTER A
a
Character.toString( 128_567 ) // FACE WITH MEDICAL MASK
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