Write a function int mystrlen(char *s) that returns the number of characters in a string wuthout strlen func [closed]

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heres what i did, i just have ne error that i cant figure out.

int mystrlen(char string[])
{
 char string1[LENGHT], string2[LENGHT];
 int len1, len2;
 char newstring[LENGHT*2];

 printf("enter first string:\n");
 len1 = mystrlen(string1);
 printf("enter second string:\n");
 len2 = mystrlen(string2);

 if(len1 == EOF || len2 == EOF)
  exit(1);

 strcpy(newstring, string1);
 strcat(newstring, string2);

 printf("%s\n", newstring);

 return 0;

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Cheating, but follows your rules...

int mystrlen( char *s)
{
    return strchr( s, '\0') - s;
}

---

You recursively call the same function on all branches. It ain't gonna work - the program will incur stack overflow and most likely crash big time.

You need to structure the program somehow like this:

int mystrlen(char string[])
{
    //compute length here
}

void testStuff()
{
    //your code here
}

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Try to read your program using Pseudocode - It will probably be easier to understand then :)

1. Declare variables string1, string2, len1, len2, newstring
2. Print a message
3. 3 Go to 1
   3.1. Declare variables string1, string2, len1, len2, newstring
   3.2. Print a message
   3.3. Go to 3.1
   ... 3.3.1 Declare variables string1, string2, len1, len2, newstring
   ... 3.3.2 .....

You see the error? :)

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To come up with a solution to your problem, you must understand that in C a "string" is an array of characters terminated by '\0'. That should be enough to help you work through a proper solution.

---

int mystrlen(char string[])
{
    int i = 0;
    while(string[i] != '\0'){
        ++i;
    }
    return i;
}