I am trying to implement the MVVM design patern for mt WPF application. In order to connect the view to the viewmodels, I use a ResourceDictionary
(used in Application.Resources
), that looks like
开发者_运维百科<DataTemplate DataType={x:Type viewmodel:SampleViewModel}>
<view:SampleView1 />
</DataTemplate>
The view models are then simply put into content presenters to display them.
Now, when the user presses a button, I'd like to display SampleViewModel
using a different view. How do I change the data template used for SampleViewModel
?
Less words more code.
As far as you said, you have the class SampleViewModel
. I added the property Title
for demonstration and ViewType
for identifying the correct view:
public enum ItemViewType { View1, View2 };
public class SampleViewModel
{
public string Title { get; set; }
public ItemViewType ViewType { get; set; }
}
The DataTemplateSelector
for two views depending on the ViewType
property:
class ItemViewTemplateSelector : DataTemplateSelector
{
public DataTemplate View1Template { get; set; }
public DataTemplate View2Template { get; set; }
public override DataTemplate SelectTemplate(object item, DependencyObject container)
{
var vm = item as SampleViewModel;
if (vm == null)
return null;
switch (vm.ViewType)
{
case ItemViewType.View1:
return View1Template;
case ItemViewType.View2:
return View2Template;
}
return null;
}
}
Xaml code:
<Window.Resources>
<DataTemplate x:Key="view1Template">
<TextBlock Text="{Binding Title}" Foreground="Red"/>
</DataTemplate>
<DataTemplate x:Key="view2Template">
<TextBox Text="{Binding Title}" />
</DataTemplate>
<local:ItemViewTemplateSelector x:Key="viewTemplateSelector"
View1Template="{StaticResource view1Template}"
View2Template="{StaticResource view2Template}"/>
</Window.Resources>
<Window.DataContext>
<local:MainViewModel/>
</Window.DataContext>
<StackPanel>
<Button Content="ChangeView" HorizontalAlignment="Center" Command="{Binding SwitchViewCommand}"/>
<ContentControl Content="{Binding ItemViewModel}" ContentTemplateSelector="{StaticResource viewTemplateSelector}"/>
</StackPanel>
The main part is in the class MainViewModel
where I've put the logic for switching views:
public class MainViewModel : ViewModelBase
{
public MainViewModel()
{
this.ItemViewModel = new SampleViewModel { Title = "Some title", ViewType = ItemViewType.View1 };
this.SwitchViewCommand = new RelayCommand(() =>
{
this.ItemViewModel.ViewType = this.ItemViewModel.ViewType == ItemViewType.View1
? ItemViewType.View2
: ItemViewType.View1;
//The magic senquence of actions which forces a contentcontrol to change the content template
var copy = this.ItemViewModel;
this.ItemViewModel = null;
this.ItemViewModel = copy;
});
}
public RelayCommand SwitchViewCommand { get; set; }
private SampleViewModel itemViewModel;
public SampleViewModel ItemViewModel
{
get { return itemViewModel; }
set
{
itemViewModel = value;
RaisePropertyChanged("ItemViewModel");
}
}
}
The SwitchViewCommand
can be any type of command, I use the command from the mvvmlight library.
Inside the handler of the command I change the type of viewmodel and update the property ItemViewModel
in a tricky way because a ContentControl
refreshes a view only if to change the Content property, and this property will not be changed unless you set a reference to different object.
I mean, even the code this.ItemViewModel = this.itemViewModel
will not change the view.
It's strange, but the workaround doesn't require much work.
You can achieve this in many different ways depends upon the architecture you want.
- You can write a custom DataTemplateSelector and use it on ContentControl.ContentTemplateSelector and choose those two templates appropriately
- If this pattern of changing the view occures in many different places and more frequent UX, I would also recommend those two views toggled using a DataTemplate.DataTrigger based on a property in SampleViewModel [I am guessing you might have a distinguishing property in the ViewModel to know that state]
You can override the mapping by placing a similar resource lower down in the tree. Since WPF will resolve the resource by searching upwards, such an override will replace your existing mapping.
精彩评论