Format text to left

I am creating a format tool that strips content from articles for print. The demo can be seen here. The full source is avaliable here.

Right now the tool strips formating and can also keep paragraphs by using nl2br What I would like to do is to be able to shift the content to the left and only have a paragraph if there is a break between the content.

for example:

This

is

the

first

paragraph

Second Paragraph

Becomes:

this is the first paragraph

Second Paragraph

I tried this by using regex to check if there were two spaces at the end but that didn't work. Here is some sample code: HTML:

<form method="post" action="">
    <textarea cols="68" rows="21" name="textinput"></textarea><br/>
    <input type="checkbox" name="keep_paragraphs" value="true" checked /> Keep Paragraphs<br/>
    <input type="checkbox" name="shift_left" value="true" /> Remove whitespace after line unless it ends in two spaces<br/>
    <input type="submit" value="Submit" />
    </form>

PHP:

$text= $_POST['textinput'];
        $p= $_POST['keep_paragraphs'];
        $lb= $_POST['shift_left'];
        if(get_magic_quotes_gpc()){
        $text = stripslashes($text);
        // strip off the slashes if they are magically added.
        }
        $text = htmlentities($text);
        //if we should keep formatting
        if($p=="true"){
            $text =nl2br($text开发者_高级运维);
        }
        if($lb=="true"){
            $text = preg_replace('/\s+/', ' ', trim($text));
        }
echo $text;

Any help on this would be great

EDIT: include example

POST textbox = "Hi Jane

How are You doing today

I hope all is well";

Most text will be coming from e-mails and other sources,basicly it needs to be super genderic.

---

The regex you need is,

/(?<!\r\n)\r\n(?=\w)/

replace it with a space.

Update

A small correction,

$text ="This
is
a
paragraph  

Second Paragraph";

$lb = "true";
if($lb=="true"){
            $text2 = preg_replace('/(?<!\r\n)\r\n(?=\w)/', ' ', trim($text));

        }

echo $text2;

---

Your can write this

$text = preg_replace('@\n([a-z])@Us', ' \1', trim($text));