having trouble coming up with a regular expression

I am having trouble coming up with a Lua 5.0 regular expression that will work for 2 scenarios.

1) expression = "[^V]Core %d+:%s*%+(%d+%.%d+)°C %(crit = %+(%d+%.%d+)°C%)" This correctly matches this string:

Core 0:      +45.0°C  (crit = +100.0°C)

2) expression = "[^V]Core %d+:%s*%+(%d+%.%d+)°C %(high = %+%d+%.%d+°C, crit = %+(%d+%.%d+)°C%)" This correctly matches this string:

Core 0:      +45.0°C  (high = +86.0°C, crit = +100.0°C)

However, I want to be able to match either string and have 2 captures: the first temperature and the critical temperature. (I don'开发者_开发知识库t need the high temperature). I tried this but no luck:

expression = "[^V]Core %d+:%s*%+(%d+%.%d+)°C  %((?:high = %+%d+%.%d+°C, )crit = %+(%d+%.%d+)°C%)"

I am in Lua but I think the regex expression syntax closely matches other languages such as Perl. Anyone have any ideas?

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The Lua string patterns are NOT regular expressions.

In order to do what you want - match two different strings - you need to actually try two matches.

local input = ... -- the input string
-- try the first pattern
local temp, crit = string.match(input, "[^V]Core %d+:%s*%+(%d+%.%d+)°C %(crit = %+(%d+%.%d+)°C%)"
-- if it didn't match, try the second match
if not temp then
    temp, crit = string.match(input, "[^V]Core %d+:%s*%+(%d+%.%d+)°C  %(high = %+%d+%.%d+°C, crit = %+(%d+%.%d+)°C%)")
end
if temp then
    -- one of the two matches are saved in temp and crit
    -- do something useful here
end

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I think you need a ? after the (?:...) group.

There's something funny going on with the number of spaces before the parens as well -- the strings and the non-working regexp have two, while the 'working' regexps have one. I'd use %s+ there for robustness.