Does anyone know how to write this Regular Expression?

I want to create a regex pattern to match a string which might include (`) not ('). For example: "This is Joe`s book", which is different from "This is Joe's book". I know how to 开发者_如何学JAVAmatch a string with (') but (`). So does anyone know how to write this Regular Expression?

Thanks!

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This should do it...

^[^']+$

The caret inside a bracket expression [^ ] is the negation operator.

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This captures strings from start ^ to end $ containing the character range in the square brackets. Note the back-tick at the end of the range.

^([a-zA-Z0-9 \.,;:\?\!`]+)$

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[^']*[`][^']*

Accept any number of characters (including 0) that are not a single quote until a you encounter a backtick, and then accept any characters (including 0) that are not a single quote after that

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If you are only wanting to test that the string has a back-tick:

/`/

Should work...

If you want to test for strings with backticks that don't contain apostrophes:

/^(?!.*').*`/

Should work...