What if I write return statement in constructor? Is it standard conformant?
struct A
{
A() { return; }
};
The above code compiles fine, without any error at ideone. But the following code doesn't:
struct A
{
A() { return 100; }
};
It gives this error at ideone:
error: returning a value from a constructor
I understand that returning value from constructor doesn't make sense at all, because it doesn't explicitly mention return type, and we cannot store the re开发者_高级运维turned value after all. But I'm curious to know :
- Which statement from the C++ Standard allows the first example but forbids the second one? Is there any explicit statement?
- Is the return type in the first example
void
? - Is there any implicit return type at all?
Yes, using return statements in constructors is perfectly standard.
Constructors are functions that do not return a value. The family of functions that do not return a value consists of: void functions, constructors and destructors. It is stated in 6.6.3/2 in the C++ standard. The very same 6.6.3/2 states that it is illegal to use return
with an argument in a function that does not return a value.
6.6.3 The return statement
2 A return statement without an expression can be used only in functions that do not return a value, that is, a function with the return type void, a constructor (12.1), or a destructor (12.4). A return statement with an expression of non-void type can be used only in functions returning a value; the value of the expression is returned to the caller of the function.
Additionally, 12.1/12 states that
12.1 Constructors
12 No return type (not even void) shall be specified for a constructor. A return statement in the body of a constructor shall not specify a return value.
Note, BTW, that in C++ it is legal to use return
with an argument in a void function, as long as the argument of return
has type void
void foo() {
return (void) 0; // Legal in C++ (but not in C)
}
This is not allowed in constructors though, since constructors are not void functions.
There's also one relatively obscure restriction relevant to the usage of return
with constructors: it is illegal to use return
in function-try-block of a constructor (with other functions it is OK)
15.3 Handling an exception
15 If a return statement appears in a handler of the function-try-block of a constructor, the program is ill formed.
Perhaps the notion of having typeless return in constructors is to control the termination of constructor function.
struct A
{
// more definitions
A()
{
if( !goodToGoOn)
return;
// the rest of the stuffs go here
}
};
A constructor by definition does return something.
For the code below,
#include <string>
#include <iostream>
using namespace std;
class dog{
private:
string _name;
string _breed;
public:
//initialise private variables to those passed in
void init(string name, string breed)
{
_name = name;
_breed = breed;
}
void bark(){cout << "BARK! BARK! My name is " << getName() << "\n";}
string getBreed(){return _breed;}
string getName(){return _name;}
};
//can run with
int main(int argc, char** argv){
//create a dog named Sally
dog sally;
//Initialise its variables
sally.init("sally", "chocolate lab");
sally.bark();
}
Here we create a void type function that initializes our dog object, then in our main function we must call that init function on our new dog object.But if use a constructor our code looks instead like
#include <string>
#include <iostream>
using namespace std;
class dog{
private:
string _name;
string _breed;
public:
//Dog constructor to initialize passed in variables
dog(string name, string breed){
_name = name;
_breed = breed;
}
void bark(){cout << "BARK! BARK! My name is " << getName() << "\n";}
string getBreed(){return _breed;}
string getName(){return _name;}
};
//can run with
int main(int argc, char** argv){
//create a dog named Sally
dog sally("sally", "chocolate lab");
sally.bark();
}
This code does essentially the same thing but it is to show that a constructor initializes the passed in variables and returns the object itself.
You cannot say
dog(string name, string breed)
{
_name = name;
_breed = breed;
return cout << "BARK! BARK! My name is " << getName() << "\n";
}
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