Generate Binary Table with Itertools

So this is what im trying

list(itertools.combinations_with_replacement('01', 2))

but this is开发者_StackOverflow社区 generating [('0', '0'), ('0', '1'), ('1', '1')]

I still need a ('1','0') tuple, is there a way to make itertools also do combinations and order?

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Use

list(itertools.product(*["01"] * 2))

instead.

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To take the cartesian product of a value with itself, you use

itertools.product("01", repeat=2)

This will give you all possible combinations.

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To generalize for lists (instead of string) use:

list(itertools.product(*[[0,1]]*2))

This will give

[(0, 0), (0, 1), (1, 0), (1, 1)]

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This program generates the numbers from 1 to 100 then converts it to binary

a=0
while a<100:
 a=a+1
 print a,"=",bin(a)