I have a php code:
<?php
$res = "";
exec("./a.out>temp", $res);
print_r(error_get_last());
print_r($res);
?>
a.out is a simple c++ program creating a socket. when I call this php code from browser an error of "Permission denied" is printed in the "temp" file.
I know this is a problem related to the right of apache user, but how to solve it?
Note: I have redirected the stderr int开发者_开发知识库o the "temp" file so that I can see what is wrong.
Thanks.
Perhaps the 'www' (or apache) users permissions are the problem.
Another option is that the socket already exists . .
Perhaps it is a problem with SE linux (if you are on linux)
/usr/sbin/setsebool httpd_can_network_connect=1
Source: http://www.rkrishardy.com/2009/12/permission-denied-13-when-opening-socket-in-php-apache/
On a side note, php can do socket stuff as-well . .
Try this
chmod 755 a.out
chmod 666 temp
Change your user to the one which is executing your apache. For example like this:
su www-data
And then execute the command again.
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