I am trying to create a Silverlight Toggle button style that would flip between a plus and a minus sign. Unfortunately it is always showing a minus sign. Can anyone tell me what's the problem with this style:
<Style x:Key="PlusMinusToggleButtonStyle" TargetType="ToggleButton">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="ToggleButton">
<Grid>
<VisualStateManager.VisualStateGroups>
<VisualStateGroup x:Name="CheckStates">
<VisualState x:Name="Unchecked">
<Storyboard>
<DoubleAnimation Storyboard.TargetName="UncheckedVisual" Storyboard.TargetProperty="Opacity" To="0" Duration="1" />
<DoubleAnimation Storyboard.TargetName="CheckedVisual" Storyboard.TargetProperty="Opacity" To="1" Duration="0" />
</Storyboard>
</VisualState>
<VisualState x:Name="Checked">
<Storyboard>
<DoubleAnimation Storyboard.TargetName="UncheckedVisual" Storyboard.TargetProperty="Opacity" To="1" Duration="0" />
<DoubleAnimation Storyboard.TargetName="CheckedVisual" Storyboard.TargetProperty="Opacity" To="0" Duration="1" />开发者_高级运维
</Storyboard>
</VisualState>
</VisualStateGroup>
</VisualStateManager.VisualStateGroups>
<Grid>
<Image x:Name="UncheckedVisual" Source="plus.png" Stretch="None" />
<Image x:Name="CheckedVisual" Source="minus.png" Stretch="None" />
</Grid>
</Grid>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
You need to expand on the DoubleAnimation, put in KeyFrame Animation in it. Also set the base opacity to 0 and then fade in the respective one you need. For example:
<VisualState x:Name="Checked">
<Storyboard>
<DoubleAnimationUsingKeyFrames Storyboard.TargetName="CheckedVisual" Storyboard.TargetProperty="Opacity">
<EasingDoubleKeyFrame KeyTime="0" Value="0"/>
<EasingDoubleKeyFrame KeyTime="0:0:1" Value="1"/>
</DoubleAnimationUsingKeyFrames>
</Storyboard>
</VisualState>
Everytime a state is changed, it goes back to the base state then to the state that was called. Because a togglebutton is always in an on or off state, it will not be in an invisible state.
精彩评论