The e开发者_开发百科xpression is:
for i=1:n
X(:,i) = [P{i}(:)];
end
where X is a DxN matrix and P is a cell-array.
reshape(cat(3,P{:}),[numel(P{1}) n])
Of course, the above solution is just for fun. I would recommend profiling both solutions and only using this one if it has a significant performance advantage.
Maintenance and readability are also very important factors to consider when writing code.
If you obtained the cell array via mat2cell
, you may be wanting to arrange blocks of an image into the columns of an array X
. This can be achieved in a single step using the command IM2COL
%# rearrange the large array so that each column of X
%# corresponds to the 4 pixels of each 2-by-2 block
X = im2col(largeArray,[2 2],'distinct');
You might be able to get away with:
P{1} = [ 1 2; 3 4];
P{2} = [ 7 8; 9 10];
P{3} = [ 11 12; 13 14];
X = [P{:}]
X =
1 2 7 8 11 12
3 4 9 10 13 14
Then some sort of reshape() to get to where you want to be.
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