I have a timestamp stored in a session (1299446702).
How can I convert that to a readable date/time in PHP? I have tried srttotime, 开发者_高级运维etc. to no avail.
Use PHP's date()
function.
Example:
echo date('m/d/Y', 1299446702);
strtotime makes a date string into a timestamp. You want to do the opposite, which is date. The typical mysql date format is date('Y-m-d H:i:s');
Check the manual page for what other letters represent.
If you have a timestamp that you want to use (apparently you do), it is the second argument of date()
.
I just added H:i:s to Rocket's answer to get the time along with the date.
echo date('m/d/Y H:i:s', 1299446702);
Output: 03/06/2011 16:25:02
$timestamp = 1465298940;
$datetimeFormat = 'Y-m-d H:i:s';
$date = new \DateTime();
// If you must have use time zones
// $date = new \DateTime('now', new \DateTimeZone('Europe/Helsinki'));
$date->setTimestamp($timestamp);
echo $date->format($datetimeFormat);
result: 2016-06-07 14:29:00
Other time zones:
- Africa
- America
- Antarctica
- Arctic
- Asia
- Atlantic
- Australia
- Europe
- Indian
- Pacific
- Others
If you are using PHP date()
, you can use this code to get the date, time, second, etc.
$time = time(); // you have 1299446702 in time
$year = $time/31556926 % 12; // to get year
$week = $time / 604800 % 52; // to get weeks
$hour = $time / 3600 % 24; // to get hours
$minute = $time / 60 % 60; // to get minutes
$second = $time % 60; // to get seconds
If anyone wants timestamp conversion directly to a DateTime object, there's a simple one-liner:
$timestamp = 1299446702;
$date = DateTime::createFromFormat('U', $timestamp);
Following @sromero comment, timezone parameter (the 3rd param in DateTime::createFromFormat()) is ignored when unix timestamp is passed, so the below code is unnecessary.
$date = DateTime::createFromFormat('U', $timestamp, new DateTimeZone('UTC'); // not needed, 3rd parameter is ignored
You may check PHP's manual for DateTime::createFromFormat for more info and options.
Try this one:
echo date('m/d/Y H:i:s', 1541843467);
$epoch = 1483228800;
$dt = new DateTime("@$epoch"); // convert UNIX timestamp to PHP DateTime
echo $dt->format('Y-m-d H:i:s'); // output = 2017-01-01 00:00:00
In the examples above "r" and "Y-m-d H:i:s" are PHP date formats, other examples:
Format Output
r ----- Wed, 15 Mar 2017 12:00:00 +0100 (RFC 2822 date)
c ----- 2017-03-15T12:00:00+01:00 (ISO 8601 date)
M/d/Y ----- Mar/15/2017
d-m-Y ----- 15-03-2017
Y-m-d H:i:s ----- 2017-03-15 12:00:00
Try it.
<?php
$timestamp=1333342365;
echo gmdate("Y-m-d\TH:i:s\Z", $timestamp);
?>
You can try this:
$mytimestamp = 1465298940;
echo gmdate("m-d-Y", $mytimestamp);
Output :
06-07-2016
Unless you need a custom date and time format, it's easier, less error-prone, and more readable to use one of the built-in date time format constants:
echo date(DATE_RFC822, 1368496604);
echo date("l M j, Y",$res1['timep']);
This is really good for converting a unix timestamp to a readable date along with day. Example:
Thursday Jul 7, 2016
echo 'Le '.date('d/m/Y', 1234567890).' à '.date('H:i:s', 1234567890);
I have used this:
<?php echo date('d/m/Y H:i a', $row['start_time']); ?>
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