Why float.NaN != double.NaN
?
while float.PositiveInfinity == double.PositiveInfinity
and float.NegativeInfinity == double.NegativeInfinity
are equal.
EXAMPLE:
bool PosInfinity = (float.Posit开发者_StackOverflow社区iveInfinity == double.PositiveInfinity); //true
bool NegInfinity = (float.NegativeInfinity == double.NegativeInfinity); //true
bool isNanEqual = (float.NaN == double.NaN); //false, WHY?
NaN
is never equal to NaN
(even within the same type). Hence why the IsNaN function exists:
Double zero = 0;
// This will return true.
if (Double.IsNaN(0 / zero))
{
Console.WriteLine("Double.IsNan() can determine whether a value is not-a-number.");
}
You should also be aware that none of the comparisons you've shown are actually occurring "as is". When you write floatValue == doubleValue
, the floats will actually be implicitly converted to doubles before the comparison occurs.
Probably because NaN != NaN
To quote wikipedia:
A comparison with a NaN always returns an unordered result even when comparing with itself.
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