Lets say a = 0x6db7
and b = 0x736
.How to compute a&b
and a|b
manually?
I am aware of bitwise operations,and I know this can be solved by convertin开发者_如何学Cg a
and b
into it's binary form and then bitwise operations and then again converting to hex,however what I am looking for is a solution that doesn't involve too much of calculation without the interdemidiate binary conversion.
Is it possible ?
Those are bitwise and
and bitwise or
. To compute them manually, convert each number to binary, then compute the result. The result of an and
will be 1 if and only if the corresponding bits are set. The result of an or
will be 1 if the corresponding bits in either one or the other or both are set:
100111 100111
&110010 |110010
------- -------
100010 110111
After that, you normally want to convert the result back to some other base (e.g., hexadecimal).
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