How to get a copy of the image from UIImagePicker

I've got a very simple app where the user selects a UIImageView and presses a button to take a photo with the camera. The image is then returned and displayed in the UIImageView.

However, since the UIImageViews are sharing the same delegate, when there's already an image in one of the UIImageViews, and I go to take a photo to be placed in another, the previous UIImageView is replaced with empty content (i.e. no image). I guess this is because they're sharing the same delegate. Is there any way I can essentially copy the image instead of referencing the delegate version of it?

Here's some sample code:

    - (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingImage:(UIImage *)image editingInfo:(NSDictionary *)editingInfo {
[picker.parentViewController dismissModalViewControllerAnimated:YES];

if (topView == YES)
{
    NSLog(@"topView = %i", topView);
    imageView.image = image;
}
else {
    NSLog(@"topView = %i", topView);
    imageView2.imag开发者_运维技巧e = image;
}

}

Thanks!

Edit: Here's the code that gets called by the IBAction on the button presses

- (IBAction) pushPick {
    topView = YES;
    UIImagePickerController *picker = [[UIImagePickerController alloc] init];
    picker.delegate = self;
    picker.sourceType = UIImagePickerControllerSourceTypeCamera;
    [self presentModalViewController:picker animated:YES];
    [picker release];
}
- (IBAction) pushPick2 {
    topView = NO;
    UIImagePickerController *picker = [[UIImagePickerController alloc] init];
    picker.delegate = self;
    picker.sourceType = UIImagePickerControllerSourceTypeCamera;
    [self presentModalViewController:picker animated:YES];
    [picker release];
}

---

Something like this:

UIImage * newImage = [UIImage imageWithCGImage:[image CGImage]];

---

use

[image copy];

But remember that you will need to release the object on dealloc