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How to concatenate string and int in C?

开发者 https://www.devze.com 2023-02-14 22:17 出处:网络
I need to form a string, inside each iteration of the loop, which contains the loop index i: for(i=0;i<100;i++) {

I need to form a string, inside each iteration of the loop, which contains the loop index i:

for(i=0;i<100;i++) {
  // Show开发者_StackOverflow社区n in java-like code which I need working in c!

  String prefix = "pre_";
  String suffix = "_suff";

  // This is the string I need formed:
  //  e.g. "pre_3_suff"
  String result = prefix + i + suffix;
}

I tried using various combinations of strcat and itoa with no luck.


Strings are hard work in C.

#include <stdio.h>

int main()
{
   int i;
   char buf[12];

   for (i = 0; i < 100; i++) {
      snprintf(buf, 12, "pre_%d_suff", i); // puts string into buffer
      printf("%s\n", buf); // outputs so you can see it
   }
}

The 12 is enough bytes to store the text "pre_", the text "_suff", a string of up to two characters ("99") and the NULL terminator that goes on the end of C string buffers.

This will tell you how to use snprintf, but I suggest a good C book!


Use sprintf (or snprintf if like me you can't count) with format string "pre_%d_suff".

For what it's worth, with itoa/strcat you could do:

char dst[12] = "pre_";
itoa(i, dst+4, 10);
strcat(dst, "_suff");


Look at snprintf or, if GNU extensions are OK, asprintf (which will allocate memory for you).

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